How to solve (1-a)-[1-(a+3)]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1-a)-[1-(a+3)] | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(1-a)-[1-(a+3)]$$

Evaluate

$3$

Solution Steps

To find the opposite of $a+3$, find the opposite of each term.

$$1-a-\left(1-a-3\right)$$

Subtract $3$ from $1$ to get $-2$.

$$1-a-\left(-2-a\right)$$

To find the opposite of $-2-a$, find the opposite of each term.

$$1-a-\left(-2\right)-\left(-a\right)$$

The opposite of $-2$ is $2$.

$$1-a+2-\left(-a\right)$$

The opposite of $-a$ is $a$.

$$1-a+2+a$$

Add $1$ and $2$ to get $3$.

$$3-a+a$$

Combine $-a$ and $a$ to get $0$.

$$3$$

Show Solution

Factor

$3$

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Evaluate

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