How to solve (1-i)-(-1+6i)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1-i)-(-1+6i) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(1-i)-(-1+6i)$$

Evaluate

$2-7i$

Show Solution

Real Part

$2$

Solution Steps

Subtract $-1+6i$ from $1-i$ by subtracting corresponding real and imaginary parts.

$$Re(1-\left(-1\right)+\left(-1-6\right)i)$$

Subtract $-1$ from $1$. Subtract $6$ from $-1$.

$$Re(2-7i)$$

The real part of $2-7i$ is $2$.

$$2$$

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Question

Evaluate

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Real Part

Solution Steps