How to solve assigment (4-2 )

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve assigment (4-2 ) | Equatix

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Question

$$( 1 ) 7 ( y - 2 ) - 5 ( y - 5 )$$

Evaluate

$2y+11$

Solution Steps

Multiply $1$ and $7$ to get $7$.

$$7\left(y-2\right)-5\left(y-5\right)$$

Use the distributive property to multiply $7$ by $y-2$.

$$7y-14-5\left(y-5\right)$$

Use the distributive property to multiply $-5$ by $y-5$.

$$7y-14-5y+25$$

Combine $7y$ and $-5y$ to get $2y$.

$$2y-14+25$$

Add $-14$ and $25$ to get $11$.

$$2y+11$$

Show Solution

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$2y+11$

Solution Steps

Multiply $1$ and $7$ to get $7$.

$$7\left(y-2\right)-5\left(y-5\right)$$

Use the distributive property to multiply $7$ by $y-2$.

$$7y-14-5\left(y-5\right)$$

Use the distributive property to multiply $-5$ by $y-5$.

$$7y-14-5y+25$$

Combine $7y$ and $-5y$ to get $2y$.

$$2y-14+25$$

Add $-14$ and $25$ to get $11$.

$$2y+11$$

Show Solution

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Evaluate

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Solution Steps