$$(1+2 \times 75+47 \times 2)/ \{ 12 \times 5-5 \times [29 \times 3+11-7 \times (21/7+19 \times 2-54/2)+(46/2+17 \times 2-7)/10] \}$$
$7$
$$\frac{1+150+94}{12\times 5-5\left(29\times 3+11-7\left(\frac{21}{7}+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{151+94}{12\times 5-5\left(29\times 3+11-7\left(\frac{21}{7}+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{12\times 5-5\left(29\times 3+11-7\left(\frac{21}{7}+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(29\times 3+11-7\left(\frac{21}{7}+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(87+11-7\left(\frac{21}{7}+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-7\left(\frac{21}{7}+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-7\left(3+19\times 2-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-7\left(3+38-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-7\left(41-\frac{54}{2}\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-7\left(41-27\right)+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-7\times 14+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(98-98+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(0+\frac{\frac{46}{2}+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(0+\frac{23+17\times 2-7}{10}\right)}$$
$$\frac{245}{60-5\left(0+\frac{23+34-7}{10}\right)}$$
$$\frac{245}{60-5\left(0+\frac{57-7}{10}\right)}$$
$$\frac{245}{60-5\left(0+\frac{50}{10}\right)}$$
$$\frac{245}{60-5\left(0+5\right)}$$
$$\frac{245}{60-5\times 5}$$
$$\frac{245}{60-25}$$
$$\frac{245}{35}$$
$$7$$
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