$$(1+3A)(x+1)-2A(x+1)+3(x+1)$$
$\left(A+4\right)\left(x+1\right)$
$$x+1+3Ax+3A-2A\left(x+1\right)+3\left(x+1\right)$$
$$x+1+3Ax+3A-2A\left(x+1\right)+3x+3$$
$$x+1+3Ax+3A-2Ax-2A+3x+3$$
$$x+1+Ax+3A-2A+3x+3$$
$$x+1+Ax+A+3x+3$$
$$4x+1+Ax+A+3$$
$$4x+4+Ax+A$$
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$Ax+4x+A+4$