$$[(1+\frac{1}{2}+\frac{1}{10}):4]^{2}\cdot(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6})^{2}:(\frac{4}{7})^{3}$$
$\frac{7}{4}=1.75$
$$\frac{\left(\frac{\frac{3}{2}+\frac{1}{10}}{4}\right)^{2}\left(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\left(\frac{\frac{8}{5}}{4}\right)^{2}\left(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\left(\frac{8}{5\times 4}\right)^{2}\left(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\left(\frac{8}{20}\right)^{2}\left(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\left(\frac{2}{5}\right)^{2}\left(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{4}{25}\left(\frac{3}{7}+\frac{4}{3}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{4}{25}\left(\frac{37}{21}-\frac{1}{2}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{4}{25}\left(\frac{53}{42}+\frac{1}{6}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{4}{25}\times \left(\frac{10}{7}\right)^{2}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{4}{25}\times \frac{100}{49}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{16}{49}}{\left(\frac{4}{7}\right)^{3}}$$
$$\frac{\frac{16}{49}}{\frac{64}{343}}$$
$$\frac{16}{49}\times \frac{343}{64}$$
$$\frac{7}{4}$$
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$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$
