How to solve (1+sqrt(3))x+2=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1+sqrt(3))x+2=0 | Equatix

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$$(1+ \sqrt{ 3 } )x+2=0$$

$x=1-\sqrt{3}\approx -0.732050808$

Use the distributive property to multiply $1+\sqrt{3}$ by $x$.

$$x+\sqrt{3}x+2=0$$

Subtract $2$ from both sides. Anything subtracted from zero gives its negation.

$$x+\sqrt{3}x=-2$$

Combine all terms containing $x$.

$$\left(1+\sqrt{3}\right)x=-2$$

The equation is in standard form.

$$\left(\sqrt{3}+1\right)x=-2$$

Divide both sides by $1+\sqrt{3}$.

$$\frac{\left(\sqrt{3}+1\right)x}{\sqrt{3}+1}=-\frac{2}{\sqrt{3}+1}$$

Dividing by $1+\sqrt{3}$ undoes the multiplication by $1+\sqrt{3}$.

$$x=-\frac{2}{\sqrt{3}+1}$$

Divide $-2$ by $1+\sqrt{3}$.

$$x=1-\sqrt{3}$$