$$(1^{2}\times71\times(8^{2}-8)\times1$$
$3976$
$$1^{3}\times 71\left(8^{2}-8\right)$$
$$1\times 71\left(8^{2}-8\right)$$
$$71\left(8^{2}-8\right)$$
$$71\left(64-8\right)$$
$$71\times 56$$
$$3976$$
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$2^{3}\times 7\times 71$
