$$(1^{3}+2^{3}+3^{3}):3^{2}+5^{12}\cdot4^{12}:20^{11}-3^{2}$$
$15$
$$\frac{1+2^{3}+3^{3}}{3^{2}}+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$\frac{1+8+3^{3}}{3^{2}}+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$\frac{9+3^{3}}{3^{2}}+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$\frac{9+27}{3^{2}}+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$\frac{36}{3^{2}}+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$\frac{36}{9}+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$4+\frac{5^{12}\times 4^{12}}{20^{11}}-3^{2}$$
$$4+\frac{244140625\times 4^{12}}{20^{11}}-3^{2}$$
$$4+\frac{244140625\times 16777216}{20^{11}}-3^{2}$$
$$4+\frac{4096000000000000}{20^{11}}-3^{2}$$
$$4+\frac{4096000000000000}{204800000000000}-3^{2}$$
$$4+20-3^{2}$$
$$24-3^{2}$$
$$24-9$$
$$15$$
Show Solution
Hide Solution
$3\times 5$