How to solve (10-6i)-(6+2i)+4i

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (10-6i)-(6+2i)+4i | Equatix

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Question

$$(10-6i)-(6+2i)+4i$$

Evaluate

$4-4i$

Solution Steps

Subtract $6+2i$ from $10-6i$ by subtracting corresponding real and imaginary parts.

$$10-6+\left(-6-2\right)i+4i$$

Subtract $6$ from $10$. Subtract $2$ from $-6$.

$$4-8i+4i$$

Combine the real and imaginary parts in numbers $4-8i$ and $4i$.

$$4+\left(-8+4\right)i$$

Add $-8$ to $4$.

$$4-4i$$

Show Solution

Real Part

$4$

Solution Steps

Subtract $6+2i$ from $10-6i$ by subtracting corresponding real and imaginary parts.

$$Re(10-6+\left(-6-2\right)i+4i)$$

Subtract $6$ from $10$. Subtract $2$ from $-6$.

$$Re(4-8i+4i)$$

Combine the real and imaginary parts in numbers $4-8i$ and $4i$.

$$Re(4+\left(-8+4\right)i)$$

Add $-8$ to $4$.

$$Re(4-4i)$$

The real part of $4-4i$ is $4$.

$$4$$

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Pre-Algebra

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Precalculus

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Example

Question

Evaluate

Solution Steps

Real Part

Solution Steps