How to solve (119/90)+(35/99)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (119/90)+(35/99) | Equatix

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$$(119/90)+(35/99)$$

$\frac{553}{330}\approx 1.675757576$

Least common multiple of $90$ and $99$ is $990$. Convert $\frac{119}{90}$ and $\frac{35}{99}$ to fractions with denominator $990$.

$$\frac{1309}{990}+\frac{350}{990}$$

Since $\frac{1309}{990}$ and $\frac{350}{990}$ have the same denominator, add them by adding their numerators.

$$\frac{1309+350}{990}$$

Add $1309$ and $350$ to get $1659$.

$$\frac{1659}{990}$$

Reduce the fraction $\frac{1659}{990}$ to lowest terms by extracting and canceling out $3$.

$$\frac{553}{330}$$

$\frac{7 \cdot 79}{2 \cdot 3 \cdot 5 \cdot 11} = 1\frac{223}{330} = 1.6757575757575758$