Solve [(15+3)-(-4-3)]/[(-48+18)/6] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$[(15+3)-(-4-3)]/[(-48+18)/6]$$

Evaluate

$-5$

Solution Steps

Add $15$ and $3$ to get $18$.

$$\frac{18-\left(-4-3\right)}{\frac{-48+18}{6}}$$

Subtract $3$ from $-4$ to get $-7$.

$$\frac{18-\left(-7\right)}{\frac{-48+18}{6}}$$

The opposite of $-7$ is $7$.

$$\frac{18+7}{\frac{-48+18}{6}}$$

Add $18$ and $7$ to get $25$.

$$\frac{25}{\frac{-48+18}{6}}$$

Add $-48$ and $18$ to get $-30$.

$$\frac{25}{\frac{-30}{6}}$$

Divide $-30$ by $6$ to get $-5$.

$$\frac{25}{-5}$$

Divide $25$ by $-5$ to get $-5$.

$$-5$$

Factor

$-5$