$$(16\sqrt{tg\ x}+ln\ x-\frac{1}{x}+\cos\ x)=$$
$\ln(x)+\cos(x)+16\sqrt{\tan(x)}-\frac{1}{x}$
$\frac{8}{\sqrt{\sin(x)\left(\cos(x)\right)^{3}}}-\sin(x)+\frac{1}{x}+\frac{1}{x^{2}}$
