Solve One of the factors of (16y ^ 2 - 1) + (1 - 4y) ^ 2 is | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( 16 y ^ { 2 } - 1 ) + ( 1 - 4 y ) ^ { 2 }$$

Evaluate

$8y\left(4y-1\right)$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(1-4y\right)^{2}$.

$$16y^{2}-1+1-8y+16y^{2}$$

Add $-1$ and $1$ to get $0$.

$$16y^{2}-8y+16y^{2}$$

Combine $16y^{2}$ and $16y^{2}$ to get $32y^{2}$.

$$32y^{2}-8y$$

Expand

$32y^{2}-8y$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(1-4y\right)^{2}$.

$$16y^{2}-1+1-8y+16y^{2}$$

Add $-1$ and $1$ to get $0$.

$$16y^{2}-8y+16y^{2}$$

Combine $16y^{2}$ and $16y^{2}$ to get $32y^{2}$.

$$32y^{2}-8y$$