$$(19-13) \div (3 \times 5-(2+7)]$$
$1$
$$\frac{6}{3\times 5-\left(2+7\right)}$$
$$\frac{6}{15-\left(2+7\right)}$$
$$\frac{6}{15-9}$$
$$\frac{6}{6}$$
$$1$$
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