Question

$$(2 { \times }^{ 2 } + { Y }^{ 2 } +3) { 2 }^{ 2 }$$

Answer

$$4*(2*^3+Y^2+3)$$

Solution


Remove parentheses.
\[(2{}^{2}+{Y}^{2}+3)\times {2}^{2}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[(2{}^{3}+{Y}^{2}+3)\times {2}^{2}\]
Simplify  \({2}^{2}\)  to  \(4\).
\[(2{}^{3}+{Y}^{2}+3)\times 4\]
Regroup terms.
\[4(2{}^{3}+{Y}^{2}+3)\]