$$[(2 \div 1 \times 2+1-1)-(10 \div 5-1 \times 2+2)]$$
$2$
$$2\times 2+1-1-\left(\frac{10}{5}-1\times 2+2\right)$$
$$4+1-1-\left(\frac{10}{5}-1\times 2+2\right)$$
$$5-1-\left(\frac{10}{5}-1\times 2+2\right)$$
$$4-\left(\frac{10}{5}-1\times 2+2\right)$$
$$4-\left(2-1\times 2+2\right)$$
$$4-\left(2-2+2\right)$$
$$4-\left(0+2\right)$$
$$4-2$$
$$2$$
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