$$(2/3-6/5) \times (4/3+10/3)$$
$-\frac{112}{45}\approx -2.488888889$
$$\left(\frac{10}{15}-\frac{18}{15}\right)\left(\frac{4}{3}+\frac{10}{3}\right)$$
$$\frac{10-18}{15}\left(\frac{4}{3}+\frac{10}{3}\right)$$
$$-\frac{8}{15}\left(\frac{4}{3}+\frac{10}{3}\right)$$
$$-\frac{8}{15}\times \frac{4+10}{3}$$
$$-\frac{8}{15}\times \frac{14}{3}$$
$$\frac{-8\times 14}{15\times 3}$$
$$\frac{-112}{45}$$
$$-\frac{112}{45}$$
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$-\frac{112}{45} = -2\frac{22}{45} = -2.488888888888889$
