$$(2\frac{3}{4}-1\frac{1}{3})\times\frac{3}{4}$$
$\frac{17}{16}=1.0625$
$$\left(\frac{8+3}{4}-\frac{1\times 3+1}{3}\right)\times \frac{3}{4}$$
$$\left(\frac{11}{4}-\frac{1\times 3+1}{3}\right)\times \frac{3}{4}$$
$$\left(\frac{11}{4}-\frac{3+1}{3}\right)\times \frac{3}{4}$$
$$\left(\frac{11}{4}-\frac{4}{3}\right)\times \frac{3}{4}$$
$$\left(\frac{33}{12}-\frac{16}{12}\right)\times \frac{3}{4}$$
$$\frac{33-16}{12}\times \frac{3}{4}$$
$$\frac{17}{12}\times \frac{3}{4}$$
$$\frac{17\times 3}{12\times 4}$$
$$\frac{51}{48}$$
$$\frac{17}{16}$$
Show Solution
Hide Solution
$\frac{17}{2 ^ {4}} = 1\frac{1}{16} = 1.0625$