How to solve (2 5/14 - 11/18)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2 5/14 - 11/18) | Equatix

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$$(2\frac{5}{14}-\frac{11}{18})$$

$\frac{110}{63}\approx 1.746031746$

Multiply $2$ and $14$ to get $28$.

$$\frac{28+5}{14}-\frac{11}{18}$$

Add $28$ and $5$ to get $33$.

$$\frac{33}{14}-\frac{11}{18}$$

Least common multiple of $14$ and $18$ is $126$. Convert $\frac{33}{14}$ and $\frac{11}{18}$ to fractions with denominator $126$.

$$\frac{297}{126}-\frac{77}{126}$$

Since $\frac{297}{126}$ and $\frac{77}{126}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{297-77}{126}$$

Subtract $77$ from $297$ to get $220$.

$$\frac{220}{126}$$

Reduce the fraction $\frac{220}{126}$ to lowest terms by extracting and canceling out $2$.

$$\frac{110}{63}$$

$\frac{2 \cdot 5 \cdot 11}{3 ^ {2} \cdot 7} = 1\frac{47}{63} = 1.746031746031746$