$$( 2 - 3 i ) ( 3 - 2 i )$$
$-13i$
$$2\times 3+2\times \left(-2i\right)-3i\times 3-3\left(-2\right)i^{2}$$
$$2\times 3+2\times \left(-2i\right)-3i\times 3-3\left(-2\right)\left(-1\right)$$
$$6-4i-9i-6$$
$$6-6+\left(-4-9\right)i$$
$$-13i$$
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$0$
$$Re(2\times 3+2\times \left(-2i\right)-3i\times 3-3\left(-2\right)i^{2})$$
$$Re(2\times 3+2\times \left(-2i\right)-3i\times 3-3\left(-2\right)\left(-1\right))$$
$$Re(6-4i-9i-6)$$
$$Re(6-6+\left(-4-9\right)i)$$
$$Re(-13i)$$
$$0$$
