How to solve (2-6i)-(7+2i)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2-6i)-(7+2i) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(2-6i)-(7+2i)$$

Evaluate

$-5-8i$

Show Solution

Real Part

$-5$

Solution Steps

Subtract $7+2i$ from $2-6i$ by subtracting corresponding real and imaginary parts.

$$Re(2-7+\left(-6-2\right)i)$$

Subtract $7$ from $2$. Subtract $2$ from $-6$.

$$Re(-5-8i)$$

The real part of $-5-8i$ is $-5$.

$$-5$$

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Question

Evaluate

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Real Part

Solution Steps