How to solve (2-x)+2(3-2x)=58

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2-x)+2(3-2x)=58 | Equatix

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3(r+2s)=2t-4

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Question

$$(2-x)+2(3-2x)=58$$

Solve for x

$x=-10$

Steps for Solving Linear Equation

Use the distributive property to multiply $2$ by $3-2x$.

$$2-x+6-4x=58$$

Add $2$ and $6$ to get $8$.

$$8-x-4x=58$$

Combine $-x$ and $-4x$ to get $-5x$.

$$8-5x=58$$

Subtract $8$ from both sides.

$$-5x=58-8$$

Subtract $8$ from $58$ to get $50$.

$$-5x=50$$

Divide both sides by $-5$.

$$x=\frac{50}{-5}$$

Divide $50$ by $-5$ to get $-10$.

$$x=-10$$

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Question

Solve for x

Steps for Solving Linear Equation