How to solve (2-x)+2(3-2x)=-29

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2-x)+2(3-2x)=-29 | Equatix

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3(r+2s)=2t-4

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Question

$$(2-x)+2(3-2x)=-29$$

Solve for x

$x = \frac{37}{5} = 7\frac{2}{5} = 7.4$

Steps for Solving Linear Equation

Use the distributive property to multiply $2$ by $3-2x$.

$$2-x+6-4x=-29$$

Add $2$ and $6$ to get $8$.

$$8-x-4x=-29$$

Combine $-x$ and $-4x$ to get $-5x$.

$$8-5x=-29$$

Subtract $8$ from both sides.

$$-5x=-29-8$$

Subtract $8$ from $-29$ to get $-37$.

$$-5x=-37$$

Divide both sides by $-5$.

$$x=\frac{-37}{-5}$$

Fraction $\frac{-37}{-5}$ can be simplified to $\frac{37}{5}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{37}{5}$$

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Solve for x

Steps for Solving Linear Equation