How to solve (2+2)(2-2)=5(2-2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2+2)(2-2)=5(2-2) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(2+2)(2-2)=5(2-2)$$

Verify

$\text{true}$

Solution Steps

Add $2$ and $2$ to get $4$.

$$4\left(2-2\right)=5\left(2-2\right)$$

Subtract $2$ from $2$ to get $0$.

$$4\times 0=5\left(2-2\right)$$

Multiply $4$ and $0$ to get $0$.

$$0=5\left(2-2\right)$$

Subtract $2$ from $2$ to get $0$.

$$0=5\times 0$$

Multiply $5$ and $0$ to get $0$.

$$0=0$$

Compare $0$ and $0$.

$$\text{true}$$

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