Solve ((2 ^ 3) ^ 5) / (2 ^ 7 * 2 ^ 4) - 1 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(2^{3})^{5}\div(2^{7}\times2^{4})-01$$

Evaluate

$16$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply $3$ and $5$ to get $15$.

$$\frac{2^{15}}{2^{7}\times 2^{4}}-0\times 1$$

To multiply powers of the same base, add their exponents. Add $7$ and $4$ to get $11$.

$$\frac{2^{15}}{2^{11}}-0\times 1$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract $11$ from $15$ to get $4$.

$$2^{4}-0\times 1$$

Calculate $2$ to the power of $4$ and get $16$.

$$16-0\times 1$$

Multiply $0$ and $1$ to get $0$.

$$16-0$$

Subtract $0$ from $16$ to get $16$.

$$16$$

Factor

$2^{4}$