$$(2^{-3}-2^{-4})(2^{-3}+2^{-4})$$
$\frac{3}{256}=0.01171875$
$$\left(\frac{1}{8}-2^{-4}\right)\left(2^{-3}+2^{-4}\right)$$
$$\left(\frac{1}{8}-\frac{1}{16}\right)\left(2^{-3}+2^{-4}\right)$$
$$\frac{1}{16}\left(2^{-3}+2^{-4}\right)$$
$$\frac{1}{16}\left(\frac{1}{8}+2^{-4}\right)$$
$$\frac{1}{16}\left(\frac{1}{8}+\frac{1}{16}\right)$$
$$\frac{1}{16}\times \frac{3}{16}$$
$$\frac{3}{256}$$
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$\frac{3}{2 ^ {8}} = 0.01171875$
