$$(2\times3^{3}\div9)-2\times(6+8)\div7$$
$2$
$$\frac{2\times 27}{9}-\frac{2\left(6+8\right)}{7}$$
$$\frac{54}{9}-\frac{2\left(6+8\right)}{7}$$
$$6-\frac{2\left(6+8\right)}{7}$$
$$6-\frac{2\times 14}{7}$$
$$6-\frac{28}{7}$$
$$6-4$$
$$2$$
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