Question

$$( 2 x , 6 y ) = ( 4 , 12 )$$

Answer

v=(x-2)/64,(3*x)/16,(6*y-(4,24*x))/128

Solution


Remove parentheses.
\[2x,6y=(4,12)\times 2x+32v\times 4\]
Simplify  \((4,12)\times 2x\)  to  \(4,12\times 2x\).
\[2x,6y=(4,12\times 2x)+32v\times 4\]
Simplify  \(12\times 2x\)  to  \(24x\).
\[2x,6y=(4,24x)+32v\times 4\]
Simplify  \(32v\times 4\)  to  \(128v\).
\[2x,6y=(4,24x)+128v\]
Switch sides.
\[(4,24x)+128v=2x,6y\]
Break down the problem into these 2 equations.
\[(4,24x)+128v=2x\]
\[(4,24x)+128v=6y\]
Solve the 1st equation: \((4,24x)+128v=2x\).
\[v=\frac{x-2}{64},\frac{3x}{16}\]
Solve the 2nd equation: \((4,24x)+128v=6y\).
\[v=\frac{6y-(4,24x)}{128}\]
Collect all solutions.
\[v=\frac{x-2}{64},\frac{3x}{16},\frac{6y-(4,24x)}{128}\]