Solve Da 1. (2x - 1) + z = (fog)(x) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( 2 x - 1 ) + 2 = ( f _ { 0 } ) ( x )$$

Solve for f_0

$f_{0}=2+\frac{1}{x}$
$x\neq 0$

Steps for Solving Linear Equation

Add $-1$ and $2$ to get $1$.

$$2x+1=f_{0}x$$

Swap sides so that all variable terms are on the left hand side.

$$f_{0}x=2x+1$$

The equation is in standard form.

$$xf_{0}=2x+1$$

Divide both sides by $x$.

$$\frac{xf_{0}}{x}=\frac{2x+1}{x}$$

Dividing by $x$ undoes the multiplication by $x$.

$$f_{0}=\frac{2x+1}{x}$$

Divide $2x+1$ by $x$.

$$f_{0}=2+\frac{1}{x}$$

Solve for x

$x=-\frac{1}{2-f_{0}}$
$f_{0}\neq 2$

Steps for Solving Linear Equation

Add $-1$ and $2$ to get $1$.

$$2x+1=f_{0}x$$

Subtract $f_{0}x$ from both sides.

$$2x+1-f_{0}x=0$$

Subtract $1$ from both sides. Anything subtracted from zero gives its negation.

$$2x-f_{0}x=-1$$

Combine all terms containing $x$.

$$\left(2-f_{0}\right)x=-1$$

Divide both sides by $2-f_{0}$.

$$\frac{\left(2-f_{0}\right)x}{2-f_{0}}=-\frac{1}{2-f_{0}}$$

Dividing by $2-f_{0}$ undoes the multiplication by $2-f_{0}$.

$$x=-\frac{1}{2-f_{0}}$$