$$(216 \div 12+2) \times (36 \times 3 \div 6+3)$$
$420$
$$\left(18+2\right)\left(\frac{36\times 3}{6}+3\right)$$
$$20\left(\frac{36\times 3}{6}+3\right)$$
$$20\left(\frac{108}{6}+3\right)$$
$$20\left(18+3\right)$$
$$20\times 21$$
$$420$$
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$2^{2}\times 3\times 5\times 7$
