How to solve (2ab + 2ab) ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2ab + 2ab) ^ 2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(2ab+2ab)^{2}$$

Evaluate

$16\left(ab\right)^{2}$

Solution Steps

Combine $2ab$ and $2ab$ to get $4ab$.

$$\left(4ab\right)^{2}$$

Expand $\left(4ab\right)^{2}$.

$$4^{2}a^{2}b^{2}$$

Calculate $4$ to the power of $2$ and get $16$.

$$16a^{2}b^{2}$$

Show Solution

Expand

$16\left(ab\right)^{2}$

Solution Steps

Combine $2ab$ and $2ab$ to get $4ab$.

$$\left(4ab\right)^{2}$$

Expand $\left(4ab\right)^{2}$.

$$4^{2}a^{2}b^{2}$$

Calculate $4$ to the power of $2$ and get $16$.

$$16a^{2}b^{2}$$

Show Solution

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Question

Evaluate

Solution Steps

Expand

Solution Steps