How to solve (2x-3-4)29-16=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2x-3-4)29-16=0 | Equatix

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$$(2x-3-4)29-16=0$$

$x = \frac{219}{58} = 3\frac{45}{58} \approx 3.775862069$

Subtract $4$ from $-3$ to get $-7$.

$$\left(2x-7\right)\times 29-16=0$$

Use the distributive property to multiply $2x-7$ by $29$.

$$58x-203-16=0$$

Subtract $16$ from $-203$ to get $-219$.

$$58x-219=0$$

Add $219$ to both sides. Anything plus zero gives itself.

$$58x=219$$

Divide both sides by $58$.

$$x=\frac{219}{58}$$