How to solve (2x-3)2=18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2x-3)2=18 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(2x-3)2=18$$

Solve for x

$x=6$

Steps for Solving Linear Equation

Divide both sides by $2$.

$$2x-3=\frac{18}{2}$$

Divide $18$ by $2$ to get $9$.

$$2x-3=9$$

Add $3$ to both sides.

$$2x=9+3$$

Add $9$ and $3$ to get $12$.

$$2x=12$$

Divide both sides by $2$.

$$x=\frac{12}{2}$$

Divide $12$ by $2$ to get $6$.

$$x=6$$

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Question

Solve for x

Steps for Solving Linear Equation