How to solve (2x-3)/5=(5x+1)/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2x-3)/5=(5x+1)/3 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$(2x-3)/5=(5x+1)/3$$

Solve for x

$x=-\frac{14}{19}\approx -0.736842105$

Steps for Solving Linear Equation

Multiply both sides of the equation by $15$, the least common multiple of $5,3$.

$$3\left(2x-3\right)=5\left(5x+1\right)$$

Use the distributive property to multiply $3$ by $2x-3$.

$$6x-9=5\left(5x+1\right)$$

Use the distributive property to multiply $5$ by $5x+1$.

$$6x-9=25x+5$$

Subtract $25x$ from both sides.

$$6x-9-25x=5$$

Combine $6x$ and $-25x$ to get $-19x$.

$$-19x-9=5$$

Add $9$ to both sides.

$$-19x=5+9$$

Add $5$ and $9$ to get $14$.

$$-19x=14$$

Divide both sides by $-19$.

$$x=\frac{14}{-19}$$

Fraction $\frac{14}{-19}$ can be rewritten as $-\frac{14}{19}$ by extracting the negative sign.

$$x=-\frac{14}{19}$$

Show Solution