Question

$$(2x+ { 1 }^{ )2 } +3=12$$

Answer

$$x=(9-1^*2)/2$$

Solution


Remove parentheses.
\[2x+{1}^{}\times 2+3=12\]
Subtract \({1}^{}\times 2\) from both sides.
\[2x+3=12-{1}^{}\times 2\]
Subtract \(3\) from both sides.
\[2x=12-{1}^{}\times 2-3\]
Simplify  \(12-{1}^{}\times 2\)  to  \(12-{1}^{}\times 2\).
\[2x=9-{1}^{}\times 2\]
Divide both sides by \(2\).
\[x=\frac{9-{1}^{}\times 2}{2}\]

Decimal Form: 4.5