Solve (2x ^ 5 + 0x ^ 4 - 2x ^ 3 + 4x ^ 2 + 0x - 3) / (x + 1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(2x^{5}+0x^{4}-2x^{3}+4x^{2}+0x-3)\div(x+1)$$

Evaluate

$\frac{2x^{5}-2x^{3}+4x^{2}-3}{x+1}$

Solution Steps

Anything times zero gives zero.

$$\frac{2x^{5}+0-2x^{3}+4x^{2}+0x-3}{x+1}$$

Anything times zero gives zero.

$$\frac{2x^{5}+0-2x^{3}+4x^{2}+0-3}{x+1}$$

Add $0$ and $0$ to get $0$.

$$\frac{2x^{5}-2x^{3}+4x^{2}-3}{x+1}$$

Expand

$\frac{2x^{5}-2x^{3}+4x^{2}-3}{x+1}$

Solution Steps

Anything times zero gives zero.

$$\frac{2x^{5}+0-2x^{3}+4x^{2}+0x-3}{x+1}$$

Anything times zero gives zero.

$$\frac{2x^{5}+0-2x^{3}+4x^{2}+0-3}{x+1}$$

Add $0$ and $0$ to get $0$.

$$\frac{2x^{5}-2x^{3}+4x^{2}-3}{x+1}$$