$$(2x^{5}y^{-4})(-8x^{-3}y^{2})$$
$-16\times \left(\frac{x}{y}\right)^{2}$
$$2^{1}x^{5}y^{-4}\left(-8\right)^{1}x^{-3}y^{2}$$
$$2^{1}\left(-8\right)^{1}x^{5}x^{-3}y^{-4}y^{2}$$
$$2^{1}\left(-8\right)^{1}x^{5-3}y^{-4+2}$$
$$2^{1}\left(-8\right)^{1}x^{2}y^{-4+2}$$
$$2^{1}\left(-8\right)^{1}x^{2}y^{-2}$$
$$-16x^{2}\times \frac{1}{y^{2}}$$
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$-\frac{32x}{y^{2}}$
