Question

$$(2x^{+}y)^{3}\div3x^{4}y^{2}$$

Answer

$$(8*x^(3*y+4)*y^2)/3$$

Solution


Use Multiplication Distributive Property: \({(xy)}^{a}={x}^{a}{y}^{a}\).
\[\frac{{2}^{3}{({x}^{y})}^{3}}{3}{x}^{4}{y}^{2}\]
Simplify  \({2}^{3}\)  to  \(8\).
\[\frac{8{({x}^{y})}^{3}}{3}{x}^{4}{y}^{2}\]
Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[\frac{8{x}^{y\times 3}}{3}{x}^{4}{y}^{2}\]
Regroup terms.
\[\frac{8{x}^{3y}}{3}{x}^{4}{y}^{2}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{8{x}^{3y}{x}^{4}{y}^{2}}{3}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{8{x}^{3y+4}{y}^{2}}{3}\]