Remove parentheses.
\[3{x}^{2}+9x+6+9{x}^{3}+3{x}^{2}-2x+5=9{x}^{3}+6{x}^{2}+7x+15\]
Cancel \(9{x}^{3}\) on both sides.
\[3{x}^{2}+9x+6+3{x}^{2}-2x+5=6{x}^{2}+7x+15\]
Simplify \(3{x}^{2}+9x+6+3{x}^{2}-2x+5\) to \(6{x}^{2}+7x+11\).
\[6{x}^{2}+7x+11=6{x}^{2}+7x+15\]
Cancel \(6{x}^{2}\) on both sides.
\[7x+11=7x+15\]
Cancel \(7x\) on both sides.
\[11=15\]
Since \(11=15\) is false, there is no solution.
[No Solution]
