$$(3/5+7/5) \times (5/3)-2$$
$\frac{4}{3}\approx 1.333333333$
$$\frac{3+7}{5}\times \frac{5}{3}-2$$
$$\frac{10}{5}\times \frac{5}{3}-2$$
$$2\times \frac{5}{3}-2$$
$$\frac{2\times 5}{3}-2$$
$$\frac{10}{3}-2$$
$$\frac{10}{3}-\frac{6}{3}$$
$$\frac{10-6}{3}$$
$$\frac{4}{3}$$
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$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$
