Solve (3(4)/(7)+4(3)/(7))\div(2)/(3)

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Question

$$(3 \frac{ 4 }{ 7 } +4 \frac{ 3 }{ 7 } ) \div \frac{ 2 }{ 3 }$$

Evaluate

$12$

Solution Steps

Multiply $3$ and $7$ to get $21$.

$$\frac{\frac{21+4}{7}+\frac{4\times 7+3}{7}}{\frac{2}{3}}$$

Add $21$ and $4$ to get $25$.

$$\frac{\frac{25}{7}+\frac{4\times 7+3}{7}}{\frac{2}{3}}$$

Multiply $4$ and $7$ to get $28$.

$$\frac{\frac{25}{7}+\frac{28+3}{7}}{\frac{2}{3}}$$

Add $28$ and $3$ to get $31$.

$$\frac{\frac{25}{7}+\frac{31}{7}}{\frac{2}{3}}$$

Since $\frac{25}{7}$ and $\frac{31}{7}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{25+31}{7}}{\frac{2}{3}}$$

Add $25$ and $31$ to get $56$.

$$\frac{\frac{56}{7}}{\frac{2}{3}}$$

Divide $56$ by $7$ to get $8$.

$$\frac{8}{\frac{2}{3}}$$

Divide $8$ by $\frac{2}{3}$ by multiplying $8$ by the reciprocal of $\frac{2}{3}$.

$$8\times \frac{3}{2}$$

Express $8\times \frac{3}{2}$ as a single fraction.

$$\frac{8\times 3}{2}$$

Multiply $8$ and $3$ to get $24$.

$$\frac{24}{2}$$

Divide $24$ by $2$ to get $12$.

$$12$$

Show Solution

Factor

$2^{2}\times 3$