$$(3-1\frac{1}{3})\times3\frac{5}{7}-1\frac{1}{14}$$
$\frac{215}{42}\approx 5.119047619$
$$\left(3-\frac{3+1}{3}\right)\times \frac{3\times 7+5}{7}-\frac{1\times 14+1}{14}$$
$$\left(3-\frac{4}{3}\right)\times \frac{3\times 7+5}{7}-\frac{1\times 14+1}{14}$$
$$\left(\frac{9}{3}-\frac{4}{3}\right)\times \frac{3\times 7+5}{7}-\frac{1\times 14+1}{14}$$
$$\frac{9-4}{3}\times \frac{3\times 7+5}{7}-\frac{1\times 14+1}{14}$$
$$\frac{5}{3}\times \frac{3\times 7+5}{7}-\frac{1\times 14+1}{14}$$
$$\frac{5}{3}\times \frac{21+5}{7}-\frac{1\times 14+1}{14}$$
$$\frac{5}{3}\times \frac{26}{7}-\frac{1\times 14+1}{14}$$
$$\frac{5\times 26}{3\times 7}-\frac{1\times 14+1}{14}$$
$$\frac{130}{21}-\frac{1\times 14+1}{14}$$
$$\frac{130}{21}-\frac{14+1}{14}$$
$$\frac{130}{21}-\frac{15}{14}$$
$$\frac{260}{42}-\frac{45}{42}$$
$$\frac{260-45}{42}$$
$$\frac{215}{42}$$
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$\frac{5 \cdot 43}{2 \cdot 3 \cdot 7} = 5\frac{5}{42} = 5.119047619047619$
