How to solve (3 - sqrt(5)) ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3 - sqrt(5)) ^ 2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(3-\sqrt{5})^{2}$$

Evaluate

$14-6\sqrt{5}\approx 0.583592135$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(3-\sqrt{5}\right)^{2}$.

$$9-6\sqrt{5}+\left(\sqrt{5}\right)^{2}$$

The square of $\sqrt{5}$ is $5$.

$$9-6\sqrt{5}+5$$

Add $9$ and $5$ to get $14$.

$$14-6\sqrt{5}$$

Show Solution

Expand

$14-6\sqrt{5}$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(3-\sqrt{5}\right)^{2}$.

$$9-6\sqrt{5}+\left(\sqrt{5}\right)^{2}$$

The square of $\sqrt{5}$ is $5$.

$$9-6\sqrt{5}+5$$

Add $9$ and $5$ to get $14$.

$$14-6\sqrt{5}$$

Show Solution

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Question

Evaluate

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Solution Steps