$$(3+2i)(2-i)$$
$8+i$
$$3\times 2+3\left(-i\right)+2i\times 2+2\left(-1\right)i^{2}$$
$$3\times 2+3\left(-i\right)+2i\times 2+2\left(-1\right)\left(-1\right)$$
$$6-3i+4i+2$$
$$6+2+\left(-3+4\right)i$$
$$8+i$$
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$8$
$$Re(3\times 2+3\left(-i\right)+2i\times 2+2\left(-1\right)i^{2})$$
$$Re(3\times 2+3\left(-i\right)+2i\times 2+2\left(-1\right)\left(-1\right))$$
$$Re(6-3i+4i+2)$$
$$Re(6+2+\left(-3+4\right)i)$$
$$Re(8+i)$$
$$8$$
