$$(3+\sqrt{3})(2+\sqrt{2})$$
$\sqrt{6}+2\sqrt{3}+3\sqrt{2}+6\approx 16.156232045$
$$6+3\sqrt{2}+2\sqrt{3}+\sqrt{3}\sqrt{2}$$
$$6+3\sqrt{2}+2\sqrt{3}+\sqrt{6}$$
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$\sqrt{6} + 2 \sqrt{3} + 3 \sqrt{2} + 6 = 16.156232045$
