$$(3^{2}-2^{2})\times(\frac{2}{3})^{-3}$$
$\frac{135}{8}=16.875$
$$\left(9-2^{2}\right)\times \left(\frac{2}{3}\right)^{-3}$$
$$\left(9-4\right)\times \left(\frac{2}{3}\right)^{-3}$$
$$5\times \left(\frac{2}{3}\right)^{-3}$$
$$5\times \frac{27}{8}$$
$$\frac{135}{8}$$
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$\frac{3 ^ {3} \cdot 5}{2 ^ {3}} = 16\frac{7}{8} = 16.875$
