$$(3^{2}+2^{2})\times(\frac{1}{2})^{3}$$
$\frac{13}{8}=1.625$
$$\left(9+2^{2}\right)\times \left(\frac{1}{2}\right)^{3}$$
$$\left(9+4\right)\times \left(\frac{1}{2}\right)^{3}$$
$$13\times \left(\frac{1}{2}\right)^{3}$$
$$13\times \frac{1}{8}$$
$$\frac{13}{8}$$
Show Solution
Hide Solution
$\frac{13}{2 ^ {3}} = 1\frac{5}{8} = 1.625$