Question

$$(3^{5})\times(6^{-3}); (9^{2})\times(6)^{-2}$$

Answer

$$243*6^-3;9^2*1/36$$

Solution


Simplify  \({3}^{5}\)  to  \(243\).
\[\begin{aligned}&243\times {6}^{-3}\\&{9}^{2}\times {6}^{-2}\end{aligned}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\begin{aligned}&243\times {6}^{-3}\\&{9}^{2}\times \frac{1}{{6}^{2}}\end{aligned}\]
Simplify  \({6}^{2}\)  to  \(36\).
\[\begin{aligned}&243\times {6}^{-3}\\&{9}^{2}\times \frac{1}{36}\end{aligned}\]