$$(3^{-1}+4^{-1}+6^{-1})^{0}$$
$1$
$$\left(\frac{1}{3}+4^{-1}+6^{-1}\right)^{0}$$
$$\left(\frac{1}{3}+\frac{1}{4}+6^{-1}\right)^{0}$$
$$\left(\frac{7}{12}+6^{-1}\right)^{0}$$
$$\left(\frac{7}{12}+\frac{1}{6}\right)^{0}$$
$$\left(\frac{3}{4}\right)^{0}$$
$$1$$
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